Z8 Is Not Dualizable
نویسنده
چکیده
منابع مشابه
An Algebra That Is Dualizable but Not Fully Dualizable
We give an example of a finite algebra which is dualizable but not fully dualizable in the sense of natural duality theory.
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We note that the Chinese remainder theorem implies that this group is isomorphic with the cylic group of order 30, Z30. 31 is prime so the only abelian group of order 31 is Z31. 32 = 2. So there are many possibilities corresponding to all of the ways we can write m1 +m2 + ...+mr = 5 with m1 ≥ m2 ≥ ... ≥ mr. The solutions are 5 = 5 which corresponds to Z32, 4 ≥ 1 giving Z16 ×Z2, 3 ≥ 2 giving Z8 ...
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